sched: Don't initialize alloc_state in build_sched_domains()
authorViresh Kumar <viresh.kumar@linaro.org>
Mon, 10 Jun 2013 10:57:18 +0000 (16:27 +0530)
committerIngo Molnar <mingo@kernel.org>
Wed, 19 Jun 2013 10:58:44 +0000 (12:58 +0200)
alloc_state will be overwritten by __visit_domain_allocation_hell() and so we
don't actually need to initialize alloc_state.

Signed-off-by: Viresh Kumar <viresh.kumar@linaro.org>
Signed-off-by: Peter Zijlstra <peterz@infradead.org>
Link: http://lkml.kernel.org/r/df57734a075cc5ad130e1ae498702e24f2529ab8.1370861520.git.viresh.kumar@linaro.org
Signed-off-by: Ingo Molnar <mingo@kernel.org>
kernel/sched/core.c

index 137dcc0..3de6264 100644 (file)
@@ -5969,7 +5969,7 @@ struct sched_domain *build_sched_domain(struct sched_domain_topology_level *tl,
 static int build_sched_domains(const struct cpumask *cpu_map,
                               struct sched_domain_attr *attr)
 {
-       enum s_alloc alloc_state = sa_none;
+       enum s_alloc alloc_state;
        struct sched_domain *sd;
        struct s_data d;
        int i, ret = -ENOMEM;